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    MLB: Danny Jansen to become first player to play for both teams in one game


    Catcher Danny Jansen is set to make history as the first player to play for both teams in the same Major League Baseball game.

    Yes, you read that right…

    The 29-year-old was batting for the Toronto Blue Jays on 26 June when their game against the Boston Red Sox was suspended because of rain.

    A day later he was traded to the Red Sox – and is now set to appear for his new team when the fixture resumes on Monday night.

    “I’m just going to put my head down and play,” Jansen said. “It’s definitely a cool thing.

    “But at the end of the day, I want to win a ball game and do everything I can to prepare for it.”

    New signings have come in midway through suspended games previously in MLB, but there has not been a scenario where a player featured against his old side.

    Remarkably, Jansen was the player batting at the plate for the Blue Jays when the game was halted two months ago.

    That means his former side will have to put up another batter in his place, while Jansen, now in the Red Sox’s uniform rather than Toronto’s, will be the catcher for the hosts at Boston’s Fenway Park.

    He will even appear in the score box and results for both teams.

    “Yeah he’s catching. Let’s make history,” said Red Sox manager Alex Cora, confirming Jansen’s appearance.

    All clear? The game begins at 00:10 BST on Tuesday.



    Read More: MLB: Danny Jansen to become first player to play for both teams in one game

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